If a given quantity of electricity liberates 0.65g of Zn2...
If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?
[Zn = 65, Hg = 201]
1.00g
2.01g
4.02g
8.04g
Correct answer is B
At the cathode, we have:
Zn2++2e−→Zn(s)
Normally, we need
2F → 65g
x → 0.65
x = 0.02F
Let us check how much mercury will be deposited by 0.02F of electricity
Hg2++2e−(aq)→Hg(s)
2F → 201g
∴ 0.02F = x
x = 2.01g