If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?
[Zn = 65, Hg = 201]

1.00g

2.01g

4.02g

8.04g

Correct answer is B

At the cathode, we have:
$Zn^{2+} + 2e^- → Zn_{(s)}$
Normally, we need
2F → 65g
x → 0.65
x = 0.02F
Let us check how much mercury will be deposited by 0.02F of electricity
$Hg^{2+} + 2e^-(aq) → Hg_{(s)}$
2F → 201g
∴ 0.02F = x
x = 2.01g

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If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?
[Zn = 65, Hg = 201]

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If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current? [Zn = 65, Hg = 201]

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Aptitude Tests

If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?
[Zn = 65, Hg = 201]