2SO2(g) + O2(g) ↔ 2SO3(g)
ΔH = -189 kJ m...
2SO2(g) + O2(g) ↔ 2SO3(g)
ΔH = -189 kJ mol-1
The equilibrium constant for the reaction above is increased by?
decreasing the temperature of the system
Increase the pressure of the system
The addition of a catalyst to the system
Increasing the surface area of the vessel
Correct answer is A
Decrease in temperature favors in Equilibrium Constant[k] for this exothermic reaction.
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