MnO−14(aq) + 8H+(aq) + Y → Mn\(^{...
MnO−14(aq) + 8H+(aq) + Y → Mn2+(aq) + 4H2O(l)
Y in the equation above represents
2e-
3e-
5e-
7e-
Correct answer is C
We want the number of charges on both sides of the equation to be the same.
i.e. number of charges on the reactant side = the number of charges on the product side.
-1 + 8 = 2
7 = 2
difference in number of charges = 5, hence Y = 5.
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