2.029 * 10-3mol dm-3
1.414 * 10-3mol dm-3
2.029 * 10-5mol dm-3
1.414 * 10-5mol dm-3
Correct answer is D
In order to calculate this, it suffices to calculate the solubility of Ag, so as to know the amount lost.
\(K_{sp} = [Ag^{+}][Cl^{-}]\)
Let the solubilty of Ag and Cl = d
\(2 \times 10^{-10} = d \times d= d^{2}\)
\(d = \sqrt{2\times10^{-10}}\)
= \(1.414 \times 10^{-5}moldm^{-3}\)
mE + nF → pG + qH. In the equation above, the equilibrium constant is given by? ...
Which of the following compounds determines the octane rating of petrol? ...
C(s) + 2S(g) → CS2(g) ΔH = +89 kJ mol-1 The chemical equation above implies that...
Which of these is NOT a physical property f water? ...
Which of the following factors does NOT affect the rate of a chemical reaction? ...
N\(_2\)O\(_4\) ⇔ 2NO\(_2\) (Δ = -ve) From the rea...
Calculate the number of moles of HCl present in 20cm3 of a 0.75M solution of the acid...