2.029 * 10-3mol dm-3
1.414 * 10-3mol dm-3
2.029 * 10-5mol dm-3
1.414 * 10-5mol dm-3
Correct answer is D
In order to calculate this, it suffices to calculate the solubility of Ag, so as to know the amount lost.
Ksp=[Ag+][Cl−]
Let the solubilty of Ag and Cl = d
2×10−10=d×d=d2
d=√2×10−10
= 1.414×10−5moldm−3
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