10\(\sqrt{3}\)
18\(\sqrt{3}\)
14\(\sqrt{3}\)
7\(\sqrt{3}\)
Correct answer is C
\(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)
= \(3\sqrt{4\times3} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)
= \(6\sqrt{3} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)
treating like a fraction, then
= \(\frac{18 + 30 - 6}{\sqrt{3}}\)
= \(\frac{42}{\sqrt{3}}\)
rationalizing
= \(14\sqrt{3}\)