In the diagram, O is the center of the circle QRS and&nbs...
In the diagram, O is the center of the circle QRS and ∠SQR = 28°. Find ∠ORS.
560
280
760
620
Correct answer is D
∠SOR = 2 × 28° = 56° (angle at the centre is twice the angle at the circumference)
From ∆SOR
|OS| = |OR| (radii)
So, ∆SOR is isosceles.
∠ORS = 1800−5602=12402 ( base angles of isosceles triangle are equal)
∴ ∠ORS = 62°
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