Find the sum of the interior angle of a pentagon.
340\(^o\)
350\(^o\)
540\(^o\)
550\(^o\)
Correct answer is C
Sum = (5 - ) 180\(^o\)
= (5 - 2) 180\(^o\) = 3 x 180\(^o\)
= 540\(^o\)
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