In the diagram above, O is the centre of the circle ABC, < ABO = 26° and < BOC = 130°. Calculate < AOC.
A.
26°
B.
13°
C.
80°
D.
102°
Correct answer is D
< BAC = \(\frac{130}{2}\) (angle subtended at the centre)
< BAC = 65°
Also, x = 26° (theorem)
y = 65° - 26° = 39°
< AOC = 180° - (39° + 39°)
= 102°