-2
2
1
-1
Correct answer is C
\(\int_{0} ^{\frac{\pi}{2}} \sin x \mathrm d x\)
= \(- \cos x |_{0} ^{\frac{\pi}{2}\)
= \(- \cos (\frac{\pi}{2}) - (- \cos 0)\)
= \(0 + 1\)
= 1
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