If the midpoint of the line PQ is (2,3) and the point P is (-2, 1), find the coordinate of the point Q.

A.

(8,6)

B.

(5,6)

C.

(0,4)

D.

(6,5)

Correct answer is D

Midpoint of a line PQ where P has coordinates (x\(_{1}\), y\(_{1}\)) and Q has coordinates (x\(_{2}\), y\(_{2}\)) is given as 

\((\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})\).

\(\therefore\) If Q has coordinates (r, s), then

\(\frac{-2 + r}{2} = 2\) and \(\frac{1 + s}{2} = 3\)

\(-2 + r = 4 \implies r = 6\)

\(1 + s = 6 \implies s = 5\)

Q = (6, 5)