The diagram shows a circle centre O. if <STR = 29 and <RST = 45, calculate the value of <STO
A.
12\(^o\)
B.
15\(^o\)
C.
29\(^o\)
D.
34\(^o\)
Correct answer is A
SRT = 180 - (46 + 29) sum of < s in a
= 180 - 75
= 105
SOT = 2 x 46 < at the centre is twice all the circle = 92
RTO = 180 - (96 + 43)
= 41
STO = 41 - 29
= 12\(^o\)