A trader realises 10x - x\(^2\) Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?

A.

7

B.

6

C.

5

D.

4

Correct answer is C

Profit (P) = 10\(_x\) − \(_x\)2

  Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0

  i.e. \(\frac{dp}{dx}\) = 0

 \(\frac{dp}{dx}\) = 10 - 2x = 0

  10 = 2x

  Then x = \(\frac{10}{2}\) = 5

  Answer is C