10001\(_{two}\)
11001\(_{two}\)
110001\(_{two}\)
11010\(_{two}\)
10001\(_{two}\)
Correct answer is D
Convert each value to decimal (base 10)
\(1011_{two}\) → 11
+ \(1101_{two}\) → 13
+ \(1001_{two}\) → 9
- \(111_{two}\) → 7
: 11 + 13 + 9 - 7 = 26
26 → \(11010_{two}\)