A wire of radius 0.2 mm is extended by 0.5% of its length...
A wire of radius 0.2 mm is extended by 0.5% of its length when supported by a load of 1.5 kg. Determine the Young's modulus for the material of the wire.
[Take g = 10 ms−2]
2.4×1010(Nm−2)
1.5×1010(Nm−2)
2.4×109(Nm−2)
1.3×1010(Nm−2)
Correct answer is A
r=0.2mm = 2×10−4 e= 0.05% of L,=0.005L, m=1.5kgg=10ms−2 , y=?,
(1000 mm = 1m)
Y = FLAe
w = mg = 1.5 × 10 = 15
A = πr2 = 227×(2×10−4)2 = 1.26×10−7(m2)
⇒ Y = 15L1.26×10−7×0.005L
⇒ Y = 151.26×10−7×0.005
⇒ Y = 156.29×10−10
Y = 2.4×1010(Nm−2)
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