A force of 10 N, acting continuously, increases the kinetic energy of an object from 20.J to 60 J. Find the distance moved by the object.
200m
40m
4m
400m
Correct answer is C
according to the work-energy theorem; Workdone = change in kinetic energy.
W = ∆ K.E
force x distance = \(K.E_2 - K.E_2\)
10 x s = 60 - 20
s = \(\frac{40}{10}\) = 4m.