45o
60o
75o
90o
Correct answer is A
Perimeter of sector = 2r + θ360o×2πr
π+8=2×4+θ3360o×2π×4
π+8+θ360o×8π
P + 8 - 8 = θπ456o
π=θπ45o
θπ=45o
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