In the figure, the value of R is
A.
3\(\Omega\)
B.
6\(\Omega\)
C.
4\(\Omega\)
D.
5\(\Omega\)
Correct answer is B
R\(_T\) = \(\frac{V}{1} = \frac{12}{2}\) = 6\(\Omega\)
R\(_T\) = 3 + \(\frac{R \times 6}{R + 6}\)
R = 6\(\Omega\)