The lower and upper fixed points marked on a Mercury-in-glass thermometer are 210mm apart. The end of the mercury column in the tube is 49mm above the lower fixed point in a room. What is the temperature of the room in degrees Celsius?
55.3\(^o\)C
23.3\(^o\)C
49.0\(^o\)C
16.43\(^o\)C
Correct answer is B
\(\frac{49 - 0}{210 - 0}\) = \(\frac{\theta - 0}{100 - \theta}\)
\(\frac{49}{210} = \frac{\theta}{100}\)
49 x 100 = 210 x \(\theta\)
\(\theta = \frac{4900}{210}\) = 23.3\(^o\)