The earth's gravitational field intensity at its surface is about
(G = 6.7 × 10\(^{-11}\)Nm\(^2\)/kg\(^2\), mass of the earth is 6 × 10\(^{24}\)kg, radius of the earth is 6.4 × 10\(^6\)m, g on the earth = 9.8m/s\(^2\))
6.7N/kg
7.9N/kg
8.0N/kg
9.8N/kg
Correct answer is D
| E | = | F
m |
= | GMm/d\(^2\)
m |
= | GM
d\(^2\) |
| E | = | 6.7 × 10\(^{-11}\) × 6 × 10\(^{24}\)
(6.4 × 10\(^6\))\(^2\) |
= | 9.8N
kg |
E = g = 9.8N/kg