\(\frac{a + bc - fg}{dg}\)
\(\frac{a - bc + fg}{dg}\)
\(\frac{a + bc - f}{dg}\)
\(\frac{a + bc - dg}{dg}\)
Correct answer is A
\(\frac{a + bc}{wd + f}\) = g(cross multiply) a = bc + wdg + fg wdg = a + bc - fg w = \(\frac{a + bc - fg}{dg}\)
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