A sector of a circle of radius 14cm containing an angle 60o is folded to form a cone. Calculate the radius of the base of the cone

A.

5\(\frac{1}{2}cm\)

B.

4\(\frac{2}{3}cm\)

C.

3\(\frac{1}{2}cm\)

D.

2\(\frac{1}{3}cm\)

Correct answer is D

Length of arc = circumference of the base of the

cone \(\frac{\theta}{360} \times 2\pi R = 2 \pi r\)

\(\frac{\theta R}{360}\) = r

r = \(\frac{60 \times 14}{360}\)

= \(\frac{7}{3} = 2\frac{1}{3}\)cm