Two forces 100N and 60N act on an object of mass 10kg as illustrated in the diagram above. Neglecting friction, calculate the acceleration of the object.
4.0\(ms^{-2}\)
13.4\(ms^{-2}\)
16.0\(ms^{-2}\)
22.6\(ms^{-2}\)
Correct answer is B
Resolving 100N into horizontal and vertical
100 sin45 = 0.7071 * 100 = 70.71
100cos45 = 70.71
Vertical forces = 100 - 70.71 → 29.29
Horizontal force = 70.71 + 60 → 130.71
Resultant of vertical and horizontal forces using pythagoras thoerem
Resultant force (F) = m * a
a = F/m → 133.9/10
a = 13.4