From the diagram above, calculate the energy stored in the capacitor
A.
4.0 x 10\(^{-2}\)J
B.
4.0 x 10\(^{-4}\)J
C.
8.0 x 10\(^{-4}\)J
D.
8.0 x 10\(^{-2}\)J
Correct answer is B
c = 8µF, v = 10v
Energy stored = \(\frac{1}{2}\) cv2
= \(\frac{1}{2}\) × (8 × 10− 6) × 102
= 4 × 10\(^{-4}\)