The p.d across a parallel-plate capacitor is 103V. If the distance between the two plates is 10cm. Calculate the magnitude of the electric field strength between the plates.

A.

1.0 x 104Vm-1

B.

1.0 x 105Vm-1

C.

1.5 x 105Vm-1

D.

2.0 x 105Vm-1

View answer & explanation

Correct answer is A

E = \(\frac{v}{d} = \frac{10^3}{0.1}\)

= 10000

= 1.0 x 104Vm-1

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