An object of volume 400cm³ and 2.5gcm^-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm^-3)

1200g

1000g

800g

400g

Correct answer is C

Mass = density x volume

400 x 2.5 = 1000g

Loss in mass = volume x density

= \(\frac{400}{2}\) x 1 = 200g

Reading on spring balance = 1000 - 200g = 800g

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An object of volume 400cm3 and 2.5gcm-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm-3)

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An object of volume 400cm³ and 2.5gcm^-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm^-3)