From the figure, calculate TH in centimeters
...
From the figure, calculate TH in centimeters
\(\frac{5}{\sqrt{3} + 1}\)
\(\frac{5}{\sqrt{3} - 1}\)
\(\frac{5}{\sqrt{3}}\)
\(\frac{\sqrt{3}}{5}\)
Correct answer is B
TH = tan 45o, TH = QH
\(\frac{TH}{5 + QH}\) = tan 30o
TH = (b + QH) tan 30o
QH = 56 (5 + QH) \(\frac{1}{\sqrt{3}}\)
QH(1 - \(\frac{1}{\sqrt{3}}\)) = \(\frac{5}{\sqrt{3}}\)
QH = \(\frac{5\sqrt{3}}{\sqrt{3}} - \frac{1}{\sqrt{3}}\)
= \(\frac{5}{\sqrt{3} - 1}\)
Similar Questions
If x = \(\frac{2}{3}\) and y = - 6, evaluate xy - \(\frac{y}{x}\)...
Solve the equation 3x\(^2\) + 25x -18 = 0...
If tan x = \(2\frac{2}{5}\), find the value of sin x; 0 \(\leq\) x \(\leq\) 90o...
If loga270 - loga10 + loga \(\frac{1}{3}\) = 2, what is the value of a?...
A man invested N5,000 for 9 months at 4%. What is the simple interest? ...
The larger value of y for which (y - 1)2 = 4y - 7 is...
Calculate the standard deviation of the following data: 7, 8, 9, 10, 11, 12, 13 ...