In the diagram, QPS = SPR, PR = 9cm. PQ = 4cm and QS = 3c...
In the diagram, QPS = SPR, PR = 9cm. PQ = 4cm and QS = 3cm, find SR.
6\(\frac{3}{4}\)cm
3\(\frac{3}{8}\)cm
4\(\frac{3}{8}\)cm
2\(\frac{3}{8}\)cm
Correct answer is A
Using angle bisector theorem: line PS bisects angle QPR
QS/QP = SR/PR
3/4 = SR/9
4SR = 27
SR = \(\frac{27}{4}\)
= 6\(\frac{3}{4}\)cm
Similar Questions
Simplify: \(\frac{5}{x - y} - \frac{4}{y - x}\)...
What is the number whose logarithm to base 10 is 2.3482? ...
The graph above is that of a quadratic function y = 2x2 - x - 6 The roots of the equation are...
The table below gives the distribution of marks obtained by a number of pupils in a class test. T...
In an acute angle-triangle XYZ, XZ = 9cm, YZ = 11cm and ∠XZY = 35° Calculate ∠YXZ, corre...
The larger value of y for which (y - 1)2 = 4y - 7 is...
The arc of a circle 50 cm long, subtends angle of 75° at the center of the circle. Find cor...