In the figure, QRS is a line, PSQ = 35o, SPR = 30o and O is the centre of the circle. Find OQP.
A.
35o
B.
30o
C.
130o
D.
25o
E.
65o
Correct answer is D
< PSQ = 35o, < SPR = 30o
O is the centre of the circle, PRQ = 65o
< OQP = 90 - 65
= 25o