Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 106Nm-2 with a volume of 10-3m3.
[R = 8.3jmol-1K-1]

A.

201oC

B.

126oC

C.

153oC

D.

185oC

View answer & explanation

Correct answer is C

T = \(\frac{PV}{nR}\) = \(\frac{7.6 x 10^6 x 10^-3}{6 x 8.3}\)

= 153oC

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