Calculate the critical angle for light traveling from water to air. (Refractive index of water = 1.33)
36.9°
41.3°
48.8°
49.2°
51.4°
Correct answer is C
critical angle formula = \(sin^{-1}\) \(\frac{n_2}{n_1}\)
→ \(sin^{-1}\) \(\frac{1}{1.33}\) = \(sin^{-1}\) 0.7518
= 48.75º