When a current of 1 .0A flows in an electrolyte for 3.0h, a mass of 1 .0g is deposited. What mass will be deposited in 10.0h if a current of 3.0A flows through the electrolyte?
30.0g
24.0g
10.0g
6.0g
0.4g
Correct answer is C
Q = charge
i = current
t = time in sec
Mass(M1)
3hours to sec
60*60*3= 10800
Mass(M2)
10hours to sec
60*60*10 = 36,000
36,000 * 3.0A = 108,000
if it takes 10800 current to discharge 1g
how much will it take 108000
10800---->1
108000---x
= 108000/10800
=10