The diagram above shows a velocity time graph representing the motion of a car. Find the total distance covered during the acceleration and retardation of the motion
A.
75m
B.
150m
C.
300m
D.
375m
Correct answer is D
Total Distance covered is the Area of the Trapezium
Area of the Trapezium = \(\frac{1}{2}\) X ( sum of parallel sides ) X height
= \(\frac{1}{2}\) X ( 30 + 45 ) X 10
: S = 375m