in the image above, an incident ray XY makes an angle of 15\( ^{\circ} \) with a fixed line AY which is normal to surface of a plane mirror if the mirroe is turned as indicated by the arrow through \( 40^{\circ} \) what angle will the reflected ray make with AY
A.
\( 25^{\circ} \)
B.
\( 40^{\circ} \)
C.
\( 15^{\circ} \)
D.
\( 55^{\circ} \)
E.
\( 95^{\circ} \)
Correct answer is E
incident ray = XY
incidence angle i = 15\( ^{\circ} \)
rotation angle θ = 40º
angle that the reflected ray make with AY = i + 2θ
= 15 + [2 * 40] = 15 + 80 = 95º