fig above represents the main sequence of energy conversion at kainji dam. what is the efficiency of the system?
A.
Q1/Q2
B.
E/Q1
C.
E/(Q1-Q2)
D.
E/(Q1-Q2)
Correct answer is B
\(efficiency = \frac{workout}{workinput}\)
= \(\frac{E}{Q_1}\)