A ray of light is incident on an equilateral triangular glass prism of refractive index 3/2, Calculate the angle through which the ray is minimally deviated in the prism
30.0\(^{\circ} \)
37.2\(^{\circ} \)
42.0\(^{\circ} \)
48.6\(^{\circ} \)
Correct answer is B
For the equilateral glass prism A = 600
\( \frac{3}{2} \text{Sin} \frac{\left( \frac{Dm + 60}{2}\right)}{\left(\frac{60}{2}\right)}= \frac{\left( \text{ Sin }\frac{Dm + 60}{2} \right)}{0.5} \\
\implies Dm = 37.2^{\circ} \)