If a force of 50N stretches a wire from 20m to 20.01m, wh...
If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?
250N
200N
100N
50N
Correct answer is A
Original length = 20m
first new length = 20.01m
first increase in length = 20.01m - 20m = 0.01m
Second new length = 20.05m
second increase in length = 20.05 - 20m = 0.05m
From hooke's law = F1e1=F2e2⟹500.01=F20.05⟹F2=50×0.050.01=250N
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