A cell whose internal resistance is 0.5Ω delivers a...
A cell whose internal resistance is 0.5Ω delivers a current of 4A to an external resistor,The loss voltage of the cell is
1.250V
2.000V
8.000V
0.125V
Correct answer is B
E = V + v
where E = emf of cell.
V = terminal p.d
v = loss voltage of the cell.
But from ohm's law V=IR ; v = Iv
\( \implies \) lost voltage = V = Ir
= 4 x 0.5
= 2.0v