A string of length 4m is extended by 0.02m when a load of...
A string of length 4m is extended by 0.02m when a load of 0.4kg is suspended at its end. What will be the length of the string when the applied force is 15N?
4.05m
4.08m
5.05m
6.08m
Correct answer is B
from hooke's law F=Ke
F1e1−F2e2therefore40.02=15e2
e1 = 0.02x154=0.075M
The new length of the string is 4 + 0.075
= 4.075
= 4.08
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