Calculate the gravitation force of attraction between two planets of 10²⁴kg and 10²⁷kg separated by a distance of 10²⁰meters.

6.67N

6.56N

7.5N

8.6N

Correct answer is A

F = (Gm₁m₂) ÷ r²

M₁ = 10₂₄Kg, M₂ = 10²⁷Kg , r = 10²

(Note: the gravitational constant of G = \(6.67 × 10^{ 7ndash; 11}\) \( Nm^2/Kg^2 \)

F = \( (6.67 × 10^{– 11 + 24 + 27)} 10^40 = 6.67 × (10^40 ÷ 10^40)

= 6.67N

f = 6.67N

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Calculate the gravitation force of attraction between two planets of 10²⁴kg and 10²⁷kg separated by a distance of 10²⁰meters.