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In the circuit diagram above, E is a battery of negligibl...

In the circuit diagram above, E is a battery of negligible internal resistance. If its emf is 9.0V. Calculate the current in the circuit 

A.

1.8A

B.

1.0A

C.

0.8A

D.

0.3A

Correct answer is B

1r=1r1+1r2

= 15+120

= 4+120=520

r = 205

= 4Ω

R = R1 + R2

= 5 + 4

= 9Ω

but V = IR

I = VR=99

= 1A