6.3A
33.3A
37.2A
40.0A
Correct answer is A
XL = \(2\pi f L\) = = 2 x 3.142 x 50 x 0.12 = 37.68\(\Omega\) Z = \(\sqrt{R^2 + X_L^2} = \sqrt{4^2 + 37.68^2}\) I = \(\frac{V}{z} = \frac{240}{37.89}\) = 6.3A
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