A block of wood of density 0.6 gcm−3, weighing 3.0...
A block of wood of density 0.6 gcm−3, weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm−3. Calculate volume of the portion immersed (g = 10ms−2)
510cm3
340cm3
254cm3
170cm3
Correct answer is B
V = MD
= 3.0610×10000.9=340