A battery of e.m.f. 12.0V and internal resistance0.5\(\Omega\) is connected to 1.5\(\Omega\) and 4.0\(\Omega\) series resistor. Calculate the terminal voltage of the battery.

A.

13.0V

B.

11.0V

C.

3.0V

D.

1.0V

View answer & explanation

Correct answer is B

\(\frac{V}{R} = \frac{E}{R + r} = \frac{V}{5.5} = \frac{12}{6}\)

v = 11.0V

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