A machine of efficiency 80% is used to lift a box. If the effort applied by the machine is twice the weight of the box. Calculate the velocity ratio of the machine
0.50
0.63
0.80
1.60
Correct answer is B
Y = \(\frac{M.A}{V.R} \times \frac{100}{1}\)
= \(\frac{\frac{1}{2}}{V.R} \times \frac{100}{1}\)
V.R = 0.625