The initial volume of water poured into a bag of dry soil was 50ml and the amount that drained through was 35mI. The percentage of water content of the fully soaked soil is therefore
46.7
25.0
20.0
30.0
Correct answer is D
Percentage of water content (retained) = \(\frac{Water absorbed}{Weight of soil} * 100\)
→ \(\frac{50 - 35}{50} * 100\)
= 30%