x2 + (1 - √13x + 1 + √13 = 0
x2 - 2x - 12 = 0
x2 - 2x + 12 = 0
x2 + 12 + 2x2 = 0
Correct answer is B
1 - √13 and 1 + √13
sum of roots - 1+√13+1−√13=2
Product of roots = (1 - √13) (1 + √13) = -12
x2 - (sum of roots) x + (product of roots) = 0
x2 - 2x - 12 = 0
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