The ice and steam point on a mercury-in-glass thermometer are 10cm and 30cm respectively. Calculate the temperature in degree Celsius when the mercury meniscus is the 14cm mark
20oC
30oC
34oC
70oC
Correct answer is A
\(\frac{x - 0}{100 - 0} = \frac{14 - 10}{30 - 10}\)
x = \(\frac{100 \times 4}{20} = 20^oC\)