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If cos2θ+18=sin2θ, fin...

If cos2θ+18=sin2θ, find tanθ.

A.

3

B.

377

C.

37

D.

7

Correct answer is B

cos2θ+18=sin2θ..........(i)

from trigometric ratios for an acute angle, where cos2θ+sin2θ=1 ........(ii)

Substitute for equation (i) in (i) = cos2θ+18=1cos2θ

= cos2θ+cos2θ=118

2cos2θ=78

cos2θ=72×8

716=cosθ

716 = 74

but cos θ = adjhyp

opp2=hyp2adj2

opp2=42(7)2

= 16 - 7

opp = 9 = 3

tanθ=oppadj

= 37

37 x 77 = 377