What are K and L respectively if \(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2).... Question 16089

What are K and L respectively if \(\frac{1}{2}\)(3y - 4x)² = (8x² + kxy + Ly²)

-12, \(\frac{9}{2}\)

-6, 9

6, 9

12, \(\frac{9}{2}\)

Correct answer is A

\(\frac{1}{2}\)(3y - 4x)² = (8x² + kxy + Ly²)

\(\frac{1}{2}\)(9y² - 24xy + 16x²) = 8x² + kxy + Ly²

\(\frac{9}{2}\)y² - 12xy) = kxy + Ly²

k = -12 ∴ L = \(\frac{9}{2}\)

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