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What are K and L respectively if \(\frac{1}{2}\)(3y - 4x)

What are K and L respectively if \(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)

A.

-12, \(\frac{9}{2}\)

B.

-6, 9

C.

6, 9

D.

12, \(\frac{9}{2}\)

View answer & explanation

Correct answer is A

\(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)

\(\frac{1}{2}\)(9y2 - 24xy + 16x2) = 8x2 + kxy + Ly2

\(\frac{9}{2}\)y2 - 12xy) = kxy + Ly2

k = -12 ∴ L = \(\frac{9}{2}\)

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