-5
-2
2
27
Correct answer is D
f(x) = x3 - 12x + 11 \(\frac{df(x)}{dx)}\) = 3x2 - 12 = 0 ∴ 3x2 - 12 = 0 \(\to\) x2m = 4 x = \(\pm\)2, f(+2) = 8 - 24 + 11 = -15 = f(-2) = (-8) + 24 + 11 = 35 - 8 = 27 ∴ maximum value = 27
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