-5
-2
2
27
Correct answer is D
f(x) = x3 - 12x + 11
df(x)dx) = 3x2 - 12 = 0
∴ 3x2 - 12 = 0 → x2m = 4
x = ±2, f(+2) = 8 - 24 + 11 = -15
= f(-2) = (-8) + 24 + 11
= 35 - 8 = 27
∴ maximum value = 27
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